10 persons take seats around a tabl...
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10 persons take seats around a table for a dinner. The probability that two specified persons are not sitting side by side is (a) 2/9 (b) 719 (C) 4/5 (d) None

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( operatorname{tot} a l sin y sin frac{10^{5} x 9}{x}=45 frac{1^{20 x}}{180} ) "U5" Days they an Seated together not togethr (let ( left.a_{1} a_{2}, a_{2} a_{3} ldots a_{10} a_{1}right) ) 0 ouys ( 80,45-10=35 ) ways possible probability is ( 35 / 45=7 / 9 )
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