Question

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Rxpressione: ( quad(x+3) ) and ( |2 x-1| )
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Two lgiven Now Plotting their individual grophs f superimposing
( |x+3|>|2 x-1| cdot x inleft[frac{-2}{3}, 4right] )

# 10 Solution of | x + 3| > 2x – 1 is (©)x(4) Mxe (4

Solution