Question

10 Solution of | x + 3| > 2x – 1 is (©)x(4) Mxe (4

JEE/Engineering Exams

Maths

Solution

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begin{tabular}{l} Rxpressione: ( quad(x+3) ) and ( |2 x-1| ) hline end{tabular} Two lgiven Now Plotting their individual grophs f superimposing ( |x+3|>|2 x-1| cdot x inleft[frac{-2}{3}, 4right] )