Question

For ( N_{2}(g)+O_{2}(g) prod_{2}=N O(theta) )
( k_{C}=frac{[N D]^{2}}{left[N_{2}right][0,]}=4 times 10^{-4}=sqrt{1} )

# 10. The equilibrium constant for the reaction ; N,(g) + 0,(g) = 2NO(g) at temperature Tis 4 x 10-4. The value of K for the reaction. NO(g)=N(8) + = 0,(E) at the same temperature is :

Solution