Question

10. (3) Let the ages of ( A, B ) and ( C ) ten years ago be ( 2 x, 3 x ) and ( 4 x ) years, respectively. Then, according to the question,
[
(2 x+10)+(3 x+10)+(4 x+10)=93
]
( Rightarrow quad 9 x+30=93 )
( Rightarrow quad 9 x=63 Rightarrow x=7 )
Thus, present age of ( A=2 x+10 ) ( =2 times 7+10=24 mathrm{yr} )

# 10. The sum of ages of A, B and C is ni 93 yr. Ten years ago, the ratio of their ages was 2:3:4. Find the present age of A. RRB NTPC (Phase-1) 2016 (1) 7 yr (2) 14 yr (3) 24 yr (4) 18 yr

Solution