Question

10. [(x-23) - 5/379/10 TT HA ETN- 17 (A)X? (B) 2x . (C) 2 (D) x.

JEE/Engineering Exams

Maths

Solution

4.0 (1 ratings)

( operatorname{sol}^{2}left[left(x^{-2 / 3}right)^{-5 / 3}right]^{9 / 10} ) ( =left[left(left(frac{1}{x}right)^{2 / 3}right)^{-5 / 3}right]^{9 / 10} ) ( =left[left(frac{1}{x}right)^{-frac{10}{9}}right]^{frac{9}{10}} ) ( sumleft[frac{1}{x}right]^{2}=x ) ( therefore ) totion (D) is correct