Question

( left(2^{3 times 6-1}+10right) div 7=6 )
( 2^{3 x-1}+10=6 times 7 )
( 2^{3 x-1}=42-10 )
( 2^{3 x} cdot 2^{-1}=32 )
( frac{2^{3 x}}{2^{3 x}}=frac{32}{2^{-1}}=32 times 2 )
( 2^{3 x}=2^{5} x^{3}= )
( 8^{3 x}=2^{6} )
( x=2 )

# 106 Find the value of x in the following b) (2321410) = 7=6

Solution