Question

( angle B R T=65^{circ} )
( angle O R+angle Q B R=angle O R T )
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(operatorname{ext} L)
]
( 25^{circ}+105 R=65^{circ} )
( 205 R=40^{circ} )
Now ( P O | s R quad angle P B S=angle O S R quad( ) dlt IN
( angle P B S=40^{circ} )
( 2 n Delta sin )
( L^{p}+sum P S A+x=180^{circ} )
( 90^{circ}+y+40^{circ}=180^{circ} )
( y=50^{circ} )

# 109] In the given figure, PQ || SR, Z SQR = 25°, ZQRT = 65°, find y. (A) 40° (B) 150° (C) 50° (D) 80°

Solution