Question

11. (1) Let ( x ) km distance be covered in ( y ) h. So, speed in first case ( =frac{x}{y} mathrm{km} / mathrm{h} ) and speed in second case ( =frac{x / 2}{2 y}=frac{x}{4 y} mathrm{km} / mathrm{h} )
( therefore quad ) Required ratio ( =frac{x}{y}: frac{x}{4 y}=1: frac{1}{4}=4: 1 )

# 11. A certain distance is covered at a certain speed. If half of the distance is covered in double time, then the ratio of the two speeds is (1) 4:1 TOT (2) 1:4 (3) 1:2 (4) 2:1

Solution