Question
11. (4) ( sin theta=frac{sqrt{3}}{2} Rightarrow sin 60^{circ}=frac{sqrt{3}}{2} )
( begin{aligned} S_{0}, &left(theta=60^{circ}right) Rightarrow quad operatorname{cosec} theta+& cot theta=operatorname{cosec} 60^{circ}+cot 60^{circ} &=frac{2}{sqrt{3}}+frac{1}{sqrt{3}} Rightarrow frac{3}{sqrt{3}} &=frac{3}{sqrt{3}} times frac{sqrt{3}}{sqrt{3}} Rightarrow frac{3 sqrt{3}}{3}=sqrt{3} end{aligned} )

11. If sin 0 = n (cosec 0 + coto) is equal to (1) 213 (3) (2 +13) 023 (4) 3
Solution
