Question

( Rightarrow operatorname{Rmax} frac{u^{2} sin 2 theta}{g} )
for max: ( Q=45^{circ} )
( begin{aligned} &=R_{max }=frac{4^{2}}{g}=400 mathrm{m} & text { Hmax } frac{4^{2} sin ^{2} Q}{2 g} end{aligned} )
D) ( 100 mathrm{m} )

# 11. The maximum horizontal range of a projectile is 400 m. The maximum height attained by it will be (a) 100 m (b) 200 m (c) 400 m (d)800 m

Solution