Question

12. (3) : The largest number of three digits
[
=999
]
( therefore ) LCM of begin{tabular}{c|c}
( 15, ) & 18,27 and 30
2 & 15,18,27,30
hline 3 & ( 15, ) & 9,27,15
hline 3 & ( 5, ) & 3,9,5
hline 3 & ( 5, ) & 1,3,5
hline 5 & ( 5, ) & 1,1,5
hline & 1,1,1,1 &
end{tabular}
[
begin{array}{l}
=2 times 3 times 3 times 3 times 5
=270
end{array}
]
Again,
[
2 7 0 longdiv { 9 9 9 } 3
]
( frac{810}{189} )
( therefore ) Required number ( =999-189=810 )

# 12. Find the largest number of three digits exactly divisible by 15, 18, 27 and 30. RRB NTPC (Phase 1) 2016 (1) 870 (2) 900 (3) 810 (4) 780

Solution