Question

( cos ^{2} 2 x=1-cos ^{2} 3 x )
( cos ^{2} 2 x=sin ^{2} 3 x )
( cos ^{2} 2 x=cos ^{2}(pi / 2-3 x) )
( 2 x=sin +(pi / 2-3 x) )
( 5 x=operatorname{ckt}+pi / 2 )

# 13 Find the general solution of x, cos2 2x + cos2 3x = 1 (A) (2k + 1) , k € I (B) (tk + 1); I (C) (3k – 1) * , ke I (D) None of these TO

Solution