Question

( begin{aligned} sqrt{3+x+sqrt{3-x}} &=2 sqrt{3+x}-sqrt{3-x} &=frac{4 sqrt{3+x}}{2 sqrt{3-x}}=frac{3}{1} & 0, ldots text { londe } end{aligned} )
( begin{array}{l}text { by componente dividende } qquadleft(j frac{a}{b}=frac{c}{d}, frac{a+b}{a-b}=frac{c+d}{c-d}right) & begin{array}{c}3+x 3+x=27-9 x 10 x=24 x=frac{24}{10}=12end{array}end{array} )

# 13+ x + 13-x 13+x-13-x ==2 then x is equal to (A) B COD

Solution