Question

( C_{1}= )
Let ( Q_{1} ) be charge on ( C_{2} ) on chargeonc
anors AB Now Voltage shald be same ( frac{O_{1}}{C_{1}}=frac{Q_{2}}{C_{2}} )
[
Q,+B_{2}=varnothing
]
( frac{Q_{1}}{C}=frac{Q_{2}}{3 C} Rightarrow Q_{1}=frac{O_{2}}{38} times K )
( Q_{1}+Q_{2}=Q )
( begin{aligned} & frac{Q_{2}}{3}+frac{partial}{2}=8 Q_{2}=frac{3}{4} theta & quad Q_{1}=frac{Q}{4} end{aligned} )
(nis ( B) frac{Q}{4}, frac{38}{4} )

# 14. Two capacitors C, = C and C = 3C are connected as shown in figure. Initially, key K is open and capacitor C, holds charge Q. After closing the key K, the charge on each capacitor at steady state will be CA (2) Q 30 3Q 3Q

Solution