Question

( operatorname{lot} 2^{x}=P )
( Rightarrow P^{prime}+frac{15}{p^{prime}}=8 )
( y^{2}-8 p^{prime}+15=0 )
( Rightarrow P^{2}-5 P^{prime}-3 P+15=0 )
( Rightarrow(P-5)left(P^{prime}-3right)=0 )
( p^{prime}=3,5 ) smalust ( therefore 2^{x}=3,5 )
( 4^{p}=4^{x}=left(2^{x}right)^{2}=9:(9) )

# 15 6. If p is the smallest value of x satisfying the equation 2+ = 8 then the value of 4P is equal to (a) 9 (b) 16 (c) 25 (d) 1

Solution