Question

( S=60 mathrm{M} )
( v=15 mathrm{Mls} quad S=(u+mathrm{y})^{t} / 2 rightarrow 60=(u+15) frac{6}{2} )
( t=6 mathrm{s} )
( u=? )

# 15. A scooter moving with constant acceleration covers the distance between two points in 6 sec. Its speed when it passes the second point is 15 m/sec. what will be its velocity when it passes from first point, if the distance between the two points is 60 metre. Ans. 5 m/sec.

Solution