Question

15. (1) Let first part ( =₹ x )
( therefore ) Second part ( =₹(10000-x) ) ( frac{x times 8 times 1}{100}+frac{(10000-x) times 10 times 1}{100} )
( Rightarrow quad 8 x+100000-10 x=92000 )
( Rightarrow quad 2 x=8000 )
( quad x=4000 )
( Rightarrow frac{10000 times 92 times 1}{100} )
Hence, first part ( =₹ 4000 )
and second part ( =₹(10000-4000) )
( =₹ 6000 )

# 15. A sum of 10,000 is lent partly at 8% and remaining at 10% per annum. If the yearly interest on the average is 9.2%, the two parts are (1) 4000, 76000 (2) * 4500, 75500 (3) 5000, 5000 (4) 5500, 4500

Solution