Question

The equation of the given circle is ( x^{2}+y^{2}=25 )
( x^{2}+y^{2}=25 )
( (x-0)^{2}+(y-0)^{2}=5^{2}, ) which is of the form ( (x-h)^{2}+(y-k)^{2}=r^{2}, ) where ( h=0, k=0, ) and ( r=5 )
Centre ( =(0,0) ) and radius ( =5 )
Distance between point (-2.5,3.5) and centre (0,0)
( =sqrt{(-2.5-0)^{2}+(3.5-0)^{2}} )
( =sqrt{6.25+12.25} )
( =sqrt{18.5} )
( =4.3(text { approx. })<5 )
since the distance between point (-2.5,3.5) and centre (0,0) of the circle is less than the radius of the circle, point (-2.5,3.5) lies inside the circle.

# 15. Does the point (-2.5. 3.5) lie inside, outside or on the ordez' * =252

Solution