Question

15. Find the equation of tangent and normal for the curve x2 + y = 36, at the point (2,1). वक्र *+y= 36 की बिन्दु (2,1) पर स्पर्श तथा अभिलम्ब रेखा का समीकरण ज्ञात कीजिये।

JEE/Engineering Exams

Maths

Solution

142

4.0 (1 ratings)

( lg ^{4} g operatorname{tangent}(2) x+y(1)=36 ) ( sin p e=(-2)^{2 x}+y=36 ) ( begin{array}{l}operatorname{Eq}^{u} g( text { normal } qquad begin{aligned}=(y-1)=-2(x-1) & y-1=-2 x+1 y+2 x-2=0 end{aligned} & y+2 x-2=0end{array} )