16. A particle starting from rest undergoes a rectilinear motion with acceleration a. The variation of a with time t is shown below. The maximum velocity attained by the particle during its motion is 10 a (m/s) 12 t's

Solution

Share

159

4.0 (1 ratings)

Download App for Answer

난 ( frac{1}{(12)} ) ( a-0=(t-12)left(frac{10-0}{0-12}right) ) ( a=(t-12)left(frac{-5}{6}right) ) ( 26 a=-5 t+60 ) ( a=frac{d v}{d x}=frac{-5 t}{6}+10 ) 94035 velowty ( mathcal{W} ) ( omega ln n=0 ) ( frac{5 t}{6}=frac{r_{0}}{t=12} ) Why ratuy [ frac{v=-5 t^{2}}{12}+10 t+c ] ( t=0 quad v=0 ) ( v=frac{-5}{x} times 12 times 14+10 times 12 ) ( begin{array}{rl}2 & -60 V_{max } 2 & 60end{array} )

159

4.0 (1 ratings)

Rate Solution

Share