Question

307 and 330 Remainders are 3 and 7 ( therefore ) Nos. would be 304 and 323 To find the greatest no. we find H ( G ) F ( 19 mid begin{array}{ccc}304 & , 323 16 & 17end{array} ) ( therefore ) the greatest no. is ( frac{19}{19} )

# 16. What is greatest number that will divide 307 and 330 leaving remainders 3 and 7 respectively? RRB NTPC (Phase 1) 2016 (1) 19 (2) 16 (3) 17 (4) 23

Solution