Question

18. cos(40° + e) - sin(50° - 0) is equal to (1) 1 (2) 0 (3) sin20 (4) cos 20

11th - 12th Class

Maths

Solution

4.0 (1 ratings)

18. ( (2) cos left(40^{circ}+thetaright)-sin left(50^{circ}-thetaright) ) ( =cos left(40^{circ}+thetaright)-sin left[90^{circ}-left(40^{circ}+thetaright)right] ) ( =cos left(40^{circ}+thetaright)-cos (40+theta)=0 )