Question

[
x=a t^{2}-t^{3}
]
( (u) otimes p_{l}+d=frac{d x}{d t}=frac{dleft(9 t^{2}-t^{3}right)}{d t}=18 t-3 t^{2} )
for Maximam Spud,

# 18. elims)-2008] The position x of a particle with respect to time t along x-axis is given by x = 9t2 - F, where x is in metres and t in second. What will be the position of this particle when it achieves maximum speed along the positive x-direction?

Solution