Question

Radius ( 20.529 times frac{n^{2}}{2} )
[
text { Given, } 0.529 times frac{n^{2}}{21}=left(0,529 times frac{4}{1}right) times 4
]
( frac{n^{2} 216}{10^{24}} )
( k cdot E=-T cdot E=+13 cdot 6 times frac{2^{2}}{n^{2}}=13 cdot 6 times frac{1}{16}=0.85 mathrm{eV} )

# 18. Kinetic energy of electron which is moving in the orbit that has its radius, four times the radius of second Bohr orbit for H-atom will be (A) 0.85 eV (B) -0.85 eV (C) 0.54 eV (D) -0.54 eV

Solution