Question

19. (3) According to the question,
and,
( therefore ) In right angled ( Delta O M A )
[
begin{aligned}
(O A)^{2} &=(O M)^{2}+(A M)^{2}
Rightarrow quad(A M)^{2} &=(O A)^{2}-(O M)^{2}
Rightarrow quad(A M)^{2} &=(20)^{2}-(16)^{2}
&=400-256=144
end{aligned}
]
( Rightarrow quad A M=12 mathrm{cm} )
Thus, length of chord, ( A B=2 . A M=2 times 12=24 mathrm{cm} )

# 19. From the centre of a circle, distance of a chord is 16 cm. If radius of the circle be 20 cm. What will be the length of the chord? (1) 6 cm (2) 12 cm (3) 24 cm (4) 36 cm

Solution