Question

we know
Noc ( H B=frac{u^{2} sin ^{2} theta}{2 times theta g} )
( frac{4 times 2 times 89}{4^{k} 2} times 5^{2}=u^{2} quad mid u=0.5 sqrt{frac{g}{2}} )
( (ln y)(b) )

# 19. Maximum height reached by projectile is 4 m. The horizontal range is 12 m. Velocity of projection is (a) 41 (b) 5.1 (c)

Solution