Question

( left(x^{2}-3 x+2right)=(x-1)(x-2)>x=1,2 )
and ( quadleft(2 x^{4}-5 x^{3}+2 x^{2}-x+2right) b_{2} f(x) )
( f(1)=2-5+2-1+2 quad=0 )
( f(2)=32-40+8-2+2=0 )
( therefore quad 1,2 ) are roots of ( f(x) )
( therefore quad(x-1)(x-2) ) is a forton.

# 2 -2 is visible by 32 without actual division, prove that 2- 5

Solution