Question

( begin{aligned} x &=3-sqrt{7} &=3-2 cdot 64 &=0.4 & x^{4}-12 x^{3}+8 x^{2}+6 x-1 =&(0.4)^{4}-12(0.4)^{3}+8(0.4)^{2}+6(0.4)-1 =& 0.0256-12(0.064)+8(0.16)+2.4-1 =& 0.0256-0.768+1.2+2.4-1 =& 1.8576 end{aligned} )

# 2. 26 2= 3-5 find the value of 29-12x3 +8 %? +62-|

Solution