Question

2. ( (1) theta=25^{circ}=frac{25 times pi}{180} ) radians
( =frac{5 pi}{36} ) radians
( theta=frac{s}{r} )
( Rightarrow r=frac{s}{theta}=frac{40}{frac{5 pi}{36}}=frac{40 times 36}{5 pi} )
( =frac{40 times 36 times 7}{5 times 22} ) metre
( =91.64 ) metre

# 2. A rail road curve is to be laid out on a circle. What radius should be used if the track is to change direction by 25° in a distance of 40 metres ? (1) 91.64 metres (2) 90.46 metres (3) 89.64 metres (4) 93.64 metres

Solution