Question

( (sin x+cos x)^{2}=1+2 cdot sin x cdot cos x )
( mid begin{array}{cc}frac{-b}{a} & =1+2 & left(frac{c}{a}right) b^{2}=a^{2}+2 a c & b^{2}-a^{2}=2 a c & =0 a^{2}-b^{2}+2 a c & =0end{array} )

# 2. If sin a & cos a are the roots of the equation ax + bx +C =0 then- (A) a' - b' + 2ac = 0 (B) a' + bº + 2ac = 0 (C) a? - b² - 2ac = 0 (D) a' + b^-2аc = 0

Solution