Question

2. Q.20 If a, ß are the root of a quadratic equat x2 – 3x + 5 = 0 then the equation whose roots are (a2 - 3a + 7) and (B2 - 3B + 7) js. (A) x2 + 4x + 1 = 0 (B) x2 - 4x + 4 = 0 (C) x2 - 4x -1 = 0 (D) x2 + 2x + 3 = 0

JEE/Engineering Exams

Maths

Solution

174

4.0 (1 ratings)

200004 ( therefore T h e q^{n}=x^{2}-left(alpha^{prime}+beta^{prime}right) x+varphi beta ) ( 2 x^{2}-4 x+4 B )