Question

3. ( (1) sec ^{2} theta-1=tan ^{2} theta ) (Trigonometric Identity)
So, ( frac{sec ^{2} theta-1}{tan ^{2} theta}=frac{tan ^{2} theta}{tan ^{2} theta}=1 )

# 2 sec 0-1 tan'e (1) 1 0 (2) 2 (3) 3 (4) 4

Solution

Instasolv

Solution