Question

0.25 moles ethanol ( frac{46.07 g}{1 text { mole ethamol }}=frac{11.52 g}{2} )
0.75 mule water ( frac{18.015 g}{1 text { mole wal } 1}=13.519 )
( 11.52 q+13.51 g=25.036 )
( 100 mathrm{g} operatorname{som}=frac{11.52 mathrm{cthan}}{25.03 mathrm{g} sin } )
( =frac{46.02 mathrm{g}}{2} mathrm{eth} )

# 2. TV TUVI (D) 2.UM Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is 0.25. Hence percentage of ethyl alcohol by weight is (A) 54% (B) 25% (C) 75% (D) 46%

Solution