20 16. A particle is moving such th...
Question
Fullscreen

20 16. A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t=0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at t = 5 s. Average velocity vector (Vav) from t= 0 to t=5 s is: (a) 2(î+1) (b) *(1 +1) (C)(139 + 141) (d) (î+j)

NEET/Medical Exams
Physics
Solution
147
Rating
4.0 (1 ratings)
Fullscreen
( begin{aligned} V_{a y}=& frac{partial_{f}-vec{r}_{i}}{t} &=frac{1.1 i+11 j}{5} &=frac{11}{5}(i+1) frac{1}{3} end{aligned} )
Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free