Question

( 8 times 2=-6 cdot 8 e v cdot 0 )

# 20. Potential energy is – 27.2 eV in second orbit of He then calculate, double of total energy in first excited state of Hydrogen atom :- (1) - 13.6 eV ) (2) - 54.4 eV (3) – 6.8 eV D (4) - 27.2 eV

Solution