Question

in this given enthalpy of combustion for ( mathrm{C} ) then reaction for combustion of carbon ( C_{(s)}+O_{2(g)} rightarrow C O_{2(g)} )
( Delta H=-393.5 mathrm{KJ} / mathrm{mol} )
and reaction for combustion of carbon-
mono-oxide is ( C O_{(g)}+frac{1}{2} O_{2(g)} rightarrow C O_{2(g)} )
( Delta H=-283 mathrm{K} / / mathrm{mol} )
reversing this equation ( C O_{2(g)} rightarrow C O_{(g)}+frac{1}{2} O_{2(g)} )
( Delta H=283 mathrm{KJ} / mathrm{mol} )
adding this equation with the equation of enthalpy of combustion of carbon ( C_{(s)}+frac{1}{2} O_{2(g)} rightarrow C O_{(g)} )
( Delta H=-393.5+283=110.5 mathrm{KJ} / mathrm{mol} )

# 20. The enthalpies of combustion of carbon and carbon monoxide are -393.5 and 283 kJ mol! respectively. The enthalpy of formation of carbon monoxide per mole :- {AIEEE-2004] (1) 110.5 kJ (2) 676.5 kJ (3) -676.5 kJ (4)-110.5 kJ

Solution