Question
( L(M(9,10,15)=96 ) ( 1936 div 90=46 ) To get remainder 7 ab 39 must be ( 96-7=39 ) subtracted,

21. What least number must be subtracted from 1936 so that the resulting number when divided by 9,10 and 15 will leave the same remainder '7' in each case? - ராமர்
Solution
