Question

( y=frac{2 x^{2}}{3-x^{2}} )
( Rightarrow 3 y-x^{2} y=2 x^{2} )
( Rightarrow quad x^{2}(2 f+y)-3 y=0 )
( x^{2}=frac{3 y}{y+2} )
( x=sqrt{frac{3 y}{y+2}} )
( y eq-2 )
34
for the to be the in sign scheme ( y geq 0 )
( y+2>0 quad y+2 leq 0 )
( therefore y in(-infty,-2) cup[0, infty) rightarrow A} )

# 22 36. Range of the function f(x) = 2X2 is (1) [0, 0) (3) (0, 2] [0, 0) (2) R (-0, -2) 4 [0, 0)

Solution