Question

# 22. If x = 7-413 and the value of (1) 0 (3) 4 RRB NTPC (Phase I) 2016 (2) 1 (4) – 4

Solution x=
7-463
vat L
√7-463 +
1
7-43
> (2)2+3) -2(2706) + -
12)2 + (32-23)(2)
+ √(2-3) ² + 1
- J (2-13)2
= (2-3) + L
(2-(3)
Taking LOM
& (2-√3)² + 1
(2-3)
→ 4 +3-413 + 1
- 2-3
- 8-43
- 2-3
4(2-23)
(
23)

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