Question

# 23.)1 से 100 तक की संख्याओं के सभी अंकों का योग है : (@5050 (2)903 30901 (4)900 (Ssc स्नातक स्तरीय Tier-II परीक्षा 01.08.2010 )

Solution 23. (3)1 से 99 तक इकाई के अंकों का योग
3 10 (1+2+3+ .....9)
9x10
= 10x-
-=450
|::1+ 2 + 3+....+r
n(n + 1)]
2
1 से 99 तक दहाई के अंकों का योग
= 10 (1+2+3+ .....9) = 450
100 के अंकों का योग = 1
:. कुल योग 450+450+ 1 = 901

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