23 A solution of sucrose (molar mas...
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23 A solution of sucrose (molar mass - 342 g mol-' has been prepared by dissolving 68.5 of sucrose in 1000 g of water. The freezing point of the solution obtained will be (K for water = 1.86 K kg mol-')

NEET/Medical Exams
Chemistry
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weight of solute ( =68-5 ) g molecular weight ( =342 ) g of solute [ begin{array}{l} text { given mass of }=1000 mathrm{g}=1 mathrm{Rg} text { solvent } end{array} ] [ begin{array}{l} K f=1.86 quad k quad text { Ro mol }^{-1} triangle T=i text { kf } m end{array} ] ( i=1 ) E- No dissociation for sucrose [ begin{array}{l} triangle T=frac{1 times 1.86 times 68-5}{342 times 189} triangle T=0.3725 end{array} ] New freezing point will be [ 273-15-0 cdot 3725=2727825 mathrm{k} ]
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