Question 
weight of solute ( =68-5 ) g
molecular weight ( =342 ) g
of solute
[
begin{array}{l}
text { given mass of }=1000 mathrm{g}=1 mathrm{Rg}
text { solvent }
end{array}
]
[
begin{array}{l}
K f=1.86 quad k quad text { Ro mol }^{-1}
triangle T=i text { kf } m
end{array}
]
( i=1 )
E- No dissociation for sucrose
[
begin{array}{l}
triangle T=frac{1 times 1.86 times 68-5}{342 times 189}
triangle T=0.3725
end{array}
]
New freezing point will be
[
273-15-0 cdot 3725=2727825 mathrm{k}
] 
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23 A solution of sucrose (molar mass - 342 g mol-' has been prepared by dissolving 68.5 of sucrose in 1000 g of water. The freezing point of the solution obtained will be (K for water = 1.86 K kg mol-')
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