Question

23. Find the factors of (x -x-132) RRB NTPC (Phase 1) 2016 (1) (x - 11)(x - 12) (2) (x + 12)(x - 11) (3) (x + 11)(x + 12) (4) (x - 12)(x + 11)

11th - 12th Class

Maths

Solution

106

4.0 (1 ratings)

23. (4) Given, ( left(x^{2}-x-132right)=0 ) ( x^{2}-12 x+11 x-132=0 ) ( x(x-12)+11(x-12)=0 ) ( (x-12)(x+11)=0 ) ( therefore ) Required fectors ( =(x-12)(x+11) )