23. If loge 2-log, 625 = logio 16 l...
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23. If loge 2-log, 625 = logio 16 log, 10, then b = (b) 2 (c) 4 (d) 5

JEE/Engineering Exams
Maths
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( =log _{e} 2 cdot log _{b} 625=frac{log 16 cdot log _{e} 10}{10} ) ( log _{e} 2 cdot log _{b} 62 r-log _{e} 10 cdot log _{10} 16=0 ) ( log _{e} 2 cdot(4) log _{b} 5-log _{e} 10.4 log _{1}=0 ) ( log _{e}^{2} log _{b} 5-log _{e} 10 . log _{10}^{2}=0 ) ( frac{log 2}{log e} frac{x log 5}{log _{5}}-frac{log _{15} x log _{2}}{log e} frac{-0}{log _{12}} ) ( log _{e}left(log _{5} 5right)-log _{e} 2=0 ) ( log _{e} 2left[log _{b} 5-1right]=0 ) ( log _{y} 5=1 ) ( 15=b )
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