Question

Xearns ( 25 % ) more than ( y ) Let ( x^{prime} ) 's earppen earning be ( x ) & y's earring be y grven that, ( y timesleft(frac{100+25}{100}right)=x )
( y frac{(125)}{100}=x )
TO find % of how much y eans less than ( x ). ( =frac{|y-x|}{x} times 100 )
( =frac{left(1 cdot frac{25-1}{x}right)^{x} cdot y times 100}{0.25left(frac{y}{x}right) times 100} )
( begin{array}{rl}= & 0.25 y times 100 5 & 1 cdot frac{125 y}{120 %} text { option }end{array} )

# 23. If X earns 25% more than Y. What per cent less does Y earn than X? (1) 16 (2) 10 (3) 20 (4) 25

Solution