Question

23. (4) According to the question,
[
begin{array}{r}
55^{circ}+9 x+16 x=180^{circ}
25 x=125^{circ}
x=5^{circ}
end{array}
]
Hence, required angles ( =9 times 5 ) and ( 16 times 5^{circ} )
[
=45^{circ} text { and } 80^{circ}
]

# 23. One angle of a triangle is 55. If the other two angles are in the ratio 9 : 16 find the angles RRB NTPC (Phase I) 2016 (1) 65 and 115 (2) 90 and 160 (3) 55 and 165 (4) 45 and 80

Solution