Question

23. Show that: (i) sin 38° cos 22° + cos 38° sin 22° = v3

JEE/Engineering Exams

Maths

Solution

133

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( quad sin 38^{circ} cos 2 i^{circ}+cos 38 sin 22^{circ} ) ( begin{aligned} text { (Rewendon, } & operatorname{Sin} A cos B+cos A sin B &=sin (A+3) Rightarrow & sin left(22^{circ}+38^{circ}right) =& sin 60^{circ}=frac{sqrt{3}}{2} end{aligned} )