Question

( 23>+p v=0 . R r quad Rightarrow quad x=frac{p_{r}}{p_{T}} )
would be
( frac{1}{0 cdot 0312}=32 g mid operatorname{mof} )
" gas is diatomic therefore we of 1 mole atom ( =16 mathrm{g} ) limol
wat of 1 atom of ( g^{4} s=frac{16}{6022 times 10^{23}} )
( =2 cdot 65 times 10^{-23} mathrm{g} / ) afom

# 23. The volume of a gas at 0°C and 700 mm of Hg pressur (cent m Cube and 700 mm of Hg pressure is 760 cc. The number of molecules present in this volume is: (cm3) [16JC110009] 24. The weight of 350 mL of a diatomic gas at 0'c and UmL of a diatomic gas at 0°C and 2 atm pressure is 1 g. The weight of one atom is: [16JC110010]

Solution