Question

To complete the loop successfully ( sqrt{2 g h}=sqrt{5 g R} )
[
R=frac{2 h}{5}=frac{2 times 5}{5}=2 mathrm{cm}
]

# 25. A frictionless track ABCDE ends in a circular loop of radius R. A body slides down the track from point A which is at heighth = 5 cm. Maximum value of R for a body to complete the loop successfully is 5 cm (a) 2 cm (0) 15 cm

Solution