Question

25. (2) According to the question,
[
begin{aligned}
x &=left(90^{circ}-xright) times frac{1}{3}+10^{circ}
3 x &=90^{circ}-x+30^{circ}
4 x &=120^{circ}
x &=30^{circ}
end{aligned}
]
Hence, the greater angle ( =90^{circ}-30^{circ}=60^{circ} )

# 25. An angle is 10° more than one third of its complement. find the greater angle. RRB NTPC (Phase I) 2016 (1) 30° (2) 60° (3) 45° (4) 75°

Solution