25 If a and B are roots of the equa...
Question
Fullscreen

25 If a and B are roots of the equation, 2 - 412 kx + 2e4in k – 1 = 0 for some k, and Q2 + B2 = 66, then a3 + b3 is equal to : [JEE Main Online - 2014] (A) 248 12 (B) 280 V2 (C) -32 V2 (D) –280 V2

JEE/Engineering Exams
Maths
Solution
145
Rating
4.0 (1 ratings)
Fullscreen

= x2-42xn+2x4-1=0 α+β =42x α+β=(2x4-1) α2+β2=66 =(α+β)2-α×β=66 =32x22(2x4-1)=66 =32x2-4x4+2=66 =16x2 -2x4+!=33 =2x4-16x2+32=0 =x4-8x2+16=0 =x4-4x2-4x2+16=0   = x2(x2 -4)-4(x2-4)=0      (x

Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free